将文件拷贝n份的bash脚本

abloz 2008-03-31
abloz 2008-03-31

测试时需要大量文件,所以写了脚本进行拷贝。有规律的文件名利于引用。

#!/bin/sh
# file name : batchcp.sh
# author: zhouhh
# blog: http://blog.csdn.net/ablo_zhou
# Email: ablozhou@gmail.com
# Date : 2008.3.31

echo "input your file name"

read  FILENAME

echo "how many times you want copy?"

read TIMES

echo "your file name is ${FILENAME}, you want to copy ${TIMES} times."

BASE=`echo ${FILENAME}|cut -d "." -f 1`
EXT=`echo ${FILENAME}|cut -d "." -f 2`

for(( i=0;i<${TIMES};i++))
do
echo "copy ${BASE}.${EXT} to ${BASE}$i.${EXT} ..."
cp "${BASE}.${EXT}" "${BASE}$i.${EXT}"
done

另一个版本

#!/bin/sh
# file name : batchcp.sh
# author: zhouhh
# blog: http://blog.csdn.net/ablo_zhou
# Email: ablozhou@gmail.com
# Date : 2008.3.31

echo "input your file name"

read  FILENAME

echo "how many times you want copy?"

read TIMES

echo "your file name is ${FILENAME}, you want to copy ${TIMES} times."
#find . and cut the left part of the file name using ##
EXT=${FILENAME##*.}
#find . and cut the right part of the file name using %
BASE=${FILENAME%.*}
echo "base:$BASE"
echo "ext:$EXT"

for(( i=0;i<${TIMES};i++))
do
echo "copy ${BASE}.${EXT} to ${BASE}$i.${EXT} ..."
cp "${BASE}.${EXT}" "${BASE}$i.${EXT}"
done

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